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3 years ago

If there are 850 students at school and eats 4oz of hamburger for lunch how many pounds did the students eat

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

1800

Step-by-step explanation:

850*4=1800

Triss [41]3 years ago

4 0

Answer:

212.5 lb

Step-by-step explanation:

850 students × 4oz/student = 3400 oz

There are 16 ounces in a pound, so:

3400 oz × (1 lb / 16 oz) = 212.5 lb

You might be interested in

The ages (in years) of the 6 employees at a particular computer store are 44, 46, 40, 34, 29, 41

son4ous [18]

step 1
compute the average: add the values and divide by 6
Average =(44+ 46+40+34+29+41)/6=39

step 2
Compute the deviations from the average
dev: (44-39)=5,
dev: (46-39)=7
dev: (40-39)=1
dev: (34-39)=-5
dev: (29-39)=-10
dev: (41-39)=2

step 3
Square the deviations and add
sum (dev^2): 5^2+7^2+1^2+-5^2+-10^2+2^2
sum (dev^2): 25+49+1+25+100+4-----> 204

step 4
Divide step #3 by the sample size=6
(typically you divide by sample size-1 to get the sample standard deviation,
but you are assuming the 6 values are the population,
so
no need to subtract 1, from the sample size.
This result is the variance
Variance =204/6=34

step 5
Standard deviation = sqrt(variance)
standard deviation= √(34)------> 5.83

the answer is
5.83

4 0

2 years ago

A high school student took two college entrance exams, scoring 1070 on the SAT and 25 on the ACT. Suppose that SAT scores have a

antoniya [11.8K]

Answer:

Due to the higher z-score, he did better on the SAT.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Determine which test the student did better on.

He did better on whichever test he had the higher z-score.

SAT:

Scored 1070, so $X = 1070$

SAT scores have a mean of 950 and a standard deviation of 155. This means that $\mu = 950, \sigma = 155$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1070 - 950}{155}$

$Z = 0.77$

ACT:

Scored 25, so $X = 25$

ACT scores have a mean of 22 and a standard deviation of 4. This means that $\mu = 22, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 22}{4}$

$Z = 0.75$

Due to the higher z-score, he did better on the SAT.

8 0

3 years ago

Whats 4x=28? whats the x for the answer?

Alik [6]

76 is the answer for x.

5 0

2 years ago

Use the Triangle Inequality Property to determine whether a triangle can be formed with the given side lengths. 4 m, 8 m, 9 m *

Illusion [34]

Answer:

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene, isosceles, equilateral and so on.

The triangle inequality property states that the sum of any two sides of a triangle must be greater than the third side. If a, b and c are the sides of a triangle then:

a + b > c; a + c > b; b + c > a

Given a triangle with side length 4 m, 8 m, 9 m:

4m + 8m = 12m > 9m

4m + 9m = 13m > 8m

8m + 9m = 17m > 4m

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m.

7 0

3 years ago

Many airline companies have begun implementing fees for checked bags. Economic theory predicts that passengers will respond to t

valentinak56 [21]

Answer:

Step-by-step explanation:

a. The hypothesis test is one tailed_____ test.

(Because we check whether sample weight is greater than hence one tailed or right tailed)

The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)

The value of the test statistic is___Mean difference/Std error = $\frac{17.1-16}{\frac{6}{\sqrt{67} } } \\=1.58$ __

b. df = 66

Reject H0 if t ≥ 1.668

c. The p-value is_____0.059444

d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.

4 0

2 years ago