How i describe the algebraic expression of n+4
1 answer:
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Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
<u>Step-by-step explanation:</u>
The ellipse is vertical so y has the biggest radius.
Major axis (y) = 20 so the y-radius is 20/2 = 10
Minor axis (x) = 14 so the x-radius is 14/2 = 7
The equation of an ellipse is: where
- (h, k) is the center of the ellipse
- a is the x-radius
- b is the y-radius
Given: a = 7, b = 10
Assume: (h, k) = (0, 0)