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Eduardwww [97]
4 years ago
14

If GET is congruent to MAP, then what corresponding parts are congruent

Mathematics
2 answers:
anastassius [24]4 years ago
8 0

Answer:

\angle G\cong \angle M

\angle E\cong \angle A

\angle T\cong \angle P

GE\cong MA

ET\cong AP

GT\cong MP

Step-by-step explanation:

We are given that

\triangle GET\cong \triangle MAP

We have to find which corresponding parts are congruent.

We know that when two triangle are congruent then their corresponding angles and their corresponding sides are congruent.

\angle G\cong \angle M

\angle E\cong \angle A

\angle T\cong \angle P

GE\cong MA

ET\cong AP

GT\cong MP

telo118 [61]4 years ago
3 0

Answer:

see below

Step-by-step explanation:

GET ≅MAP

Then

<G = <M

<E = <A

<T = <P

GE = MA

ET = AP

GT = MP

by corresponding parts of congruent triangles are congruent

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Which set of ordered pairs does not represent a function?
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7 0
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Use euler's theorem to find a number x between 0 and 28 with x85 congruent to 6 modulo 35.
Elan Coil [88]
Problem: find 0 &le; x &le; 28 such that x^85 ≡ 6 modulo 35.

By Fermat-Euler theorem:
If a and n are coprime, i.e. (a,n)=1, then
a^phi(n) ≡ 1 mod n  
where phi(n)=totient function, the number of positive integers less than n that is coprime with n.

for n=35, phi(35)=24 calculated as follows:
There are 10 positive integers from 1 to 34 which are NOT coprime with 35, namely {5,7,10,14,15,20,21,25,28,30}.Therefore phi(35)=34-10=24

From Fermat-Euler theorem, 
x^(phi(35) = x^24 ≡ 1 modulo 35  since (24,35)=1, i.e. 24 and 35 are coprime.
=>
x^12 ≡ &pm; 1 modulo 35. ...........(1)

and 

x^85 ≡ x^(85-3*24) ≡ x^(85-72) ≡ x^(13) ≡ 6 mod 35 ............(2)

Substituting (1) in (2)
x^(12)*x ≡ 6 mod 35
=>
(+1)*x = 6 mod 35   or  (-1)*x ≡ 6 mod 35
x ≡ 6 mod 35           x ≡ -6 mod 35   (rejected)

=>  x=6 

So

6^85 ≡ 6 mod 35


If any clarifications are needed or if you find any errors, please post.
5 0
3 years ago
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