Fill in each slot in the square with variables <em>a</em>, <em>b</em>, <em>c</em>, <em>d</em>, and <em>e</em>, in order from left-to-right, top-to-bottom. In a magic square, the sums across rows, columns, and diagonals all add up to the same number called the <em>magic sum</em>.
The magic sum is -3.9, since "diagonal 2" (bottom left to top right) has all the information we need:
3 + (-1.3) + (-5.6) = -3.9
Use this to find the remaining elements
<em>a</em> + <em>b</em> + (-5.6) = -3.9
<em>c</em> + (-1.3) + <em>d</em> = -3.9
3 + <em>e</em> + 0.02 = -3.9
<em>a</em> + <em>c</em> + 3 = -3.9
<em>b</em> + (-1.3) + <em>e</em> = -3.9
(-5.6) + <em>d</em> + 0.02 = -3.9
- diagonal 1 (top left to bottom right):
<em>a</em> + (-1.3) + 0.02 = -3.9
You will find
<em>a</em> = -2.62
<em>b</em> = 4.32
<em>c</em> = -4.28
<em>d</em> = 1.68
<em>e</em> = -6.92
the question is not so clear
is it (x+3)/3 or what you have written is correct
Step-by-step explanation:
Answer:
not possible, bother terms have to contain a letter variable
6m+23
You have to use distributive property, so 15x2=30 and 2x3m= 6m. You then subtract 30 from 7 and get 23.
