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Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050

attashe74 [19]

The answer is mean = 13,027; median = 12,200; no mode

Let's rearrange values from the lowest to the highest:
11350, 12050, 12200, 13325, 16211

The mean is the sum of all values divided by the number of values:
(11350 + 12050 + 12200 + 13325 + 16211)/5 ≈ 13027

The median is the middle value. If there is an odd number of data, then the median is the value in the middle. In the data set 11350, 12050, 12200, 13325, 16211, the median (the middle value) is 12200

The mode is the value that occurs most frequently. Since none of the number does not occur most frequently, there is no mode.

7 0

3 years ago

Read 2 more answers

27÷819= give me the quotient for 27÷819

Dafna11 [192]

Answer:

0.03296703

Step-by-step explanation: Just put this in the calculator and it will give you an answer. If youb dont have a calculator then look it up on the computer!

~Cake Queen (:

3 0

3 years ago

A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim

valentinak56 [21]

45 dimes and 93 nickels were in bank

Solution:

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

Given that There are three more than twice as many nickels as there are dimes

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

Also given that coin bank that excepts only nickels and dimes contains $9.15

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

$n \times 0.05 + d \times 0.10 = 9.15$

0.05n + 0.10d = 9.15 ---- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

Thus 45 dimes and 93 nickels were in bank

3 0

3 years ago

jacob wants to buy packets of fruit juice. on tuesday, he buys 8 packets of orange and 6 packets of Apple the packets make a tot

ioda

Answer:

Each packet of orange can make 2 cups of juice and each packets of Apple can make 3 cups of juice.

Step-by-step explanation:

Let number of cups of juice in each packet of orange be 'x'.

Let number of cups of juice in each pack of apples be 'y'.

Given:

On Tuesday;

Number of packets of oranges = 8

Number of packets of apples = 6 packets.

Amount of fruit juice = 34 cups

So we can say that;

Amount of fruit juice is equal to sum of Number of packets of oranges multiplied by number of cups of juice in each packet of orange and Number of packets of apples multiplied by number of cups of juice in each pack of apples.

framing in equation form we get;

$8x+6y=34 \ \ \ \ equation \ 1$

On Wednesday;

Number of packets of oranges = 14

Number of packets of apples = 6

Amount of fruit juice = 46 cups

So we can say that;

Amount of fruit juice is equal to sum of Number of packets of oranges multiplied by number of cups of juice in each packet of orange and Number of packets of apples multiplied by number of cups of juice in each pack of apples.

framing in equation form we get;

$14x+6y=46 \ \ \ \ equation \ 2$