Answer:
D
Step-by-step explanation:
sorry if the answer is wrong
Answer:
The perimeter of a rectangle is the sum of both lengths and both widths, which is equal to 54 meters. Let's call Length L and Width W.
The question is saying this: L = 3 meters + 3(W). We have 2 variables, which means we need at least 2 equations to solve. So far we have one, our second equation is from the perimeter.
2 lengths + 2 Widths = 54. Now, it's just a plug and chug.
2(3 + 3W) + 2W = 54.
6 + 6W + 2W = 54
8W = 48
W=6
L = 3 + 3(6) = 21
To double check: 2(21) + 2(6) = 42 + 12 = 54
The Width is 6 meters, and the Length is 21 meters.
In 57,733 the values are:
5 is for tens
The first 7 is for ones
The second 7 is for tenths
The first 3 is for hundredths
The second 3 is for thousandths
Two set of digit in which one digit is ten times as great as the other are 3 and 3, as well as 7 and 7
It's because 0,03 is ten times as much as 0,003 and 7 is ten times as much as 0,7.
1 dozen = 12
Divide 941 by 12:
941 / 12 = 78.42
So the greatest number of dozens he can make is 78.
