The question means that when the number is 1 more than a multiple of 4 and two more than a multiple of 5. Write out multiples of 4 with one added on to them.
5,9,13,17,21,
Then write out multiples of 5 with one added on to them
7,12,17,22,
The smallest number that both lists share is 17, so that is the answer
Step-by-step explanation:
The factorisation of 49b^2 - 81 is (7b - 9)(7b + 9). This is because 49 and 81 are the squares of 7 and 9 respectively, so these must be multiplied together. b^2 is b x b. Finally, it must be -9 and +9 to make -81, because when the signs are the same the result is a positive number
Answer:
John would have 0.79 feet of wire left over after fixing the lamp
Step-by-step explanation:
Given:
Length of the wire John needed for fixing the lamp = 13.71 feet
Length of wire John bought from the hardware store = 
To Find:
Length of wire left with John after fixing the lamp = ?
Solution:
Lets first convert the mixed fraction into decimal form
=> 
=>
=> 14.5
So John Bought 14.5 feet of wire
Now
let the wire that is left with John after Fixing the lamp be X
Then,
X = length of wire john bought - Length of wire needed for fixing the lamp
X= 14.5 - 13.71
X = 0.79