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eduard
3 years ago
10

What is the factorization of 49b2 − 81?

Mathematics
2 answers:
worty [1.4K]3 years ago
8 0

Step-by-step explanation:

The factorisation of 49b^2 - 81 is (7b - 9)(7b + 9). This is because 49 and 81 are the squares of 7 and 9 respectively, so these must be multiplied together. b^2 is b x b. Finally, it must be -9 and +9 to make -81, because when the signs are the same the result is a positive number

Bingel [31]3 years ago
5 0

Answer:

(7b - 9)(7b + 9)

Step-by-step explanation:

49b2 - 81

49 - 7 x 7

b2 - b x b

81 - 9 x 9

(a + b) (a - b) = a2 - b2

(7b - 9)(7b + 9)

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Answer:
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Step-by-step explanation:

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Step-by-step explanation:

Finding the Number

To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.

Equation:

Let "x" be the number.

4 is divided by a number - 4/x

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