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Darya [45]
3 years ago
9

The relationship 1/sin(θ) is equivalent to which of the following trigonometric functions?

Mathematics
2 answers:
Helga [31]3 years ago
6 0
\bf sin(\theta)=\cfrac{1}{csc(\theta)}
\qquad 
% cosine
cos(\theta)=\cfrac{1}{sec(\theta)}
\qquad 
% tangent
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\\\\\\
% cotangent
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad 
% cosecant
\boxed{csc(\theta)=\cfrac{1}{sin(\theta)}}
\qquad 
% secant
sec(\theta)=\cfrac{1}{cos(\theta)}
luda_lava [24]3 years ago
4 0

Answer:

Option B is the correct answer.

Step-by-step explanation:

We have the following trigonometric relations

      cosec\theta =\frac{1}{sin\theta }\\\\sec\theta =\frac{1}{cos\theta }\\\\cot\theta =\frac{1}{tan\theta }\\\\cot\theta =\frac{cos\theta}{sin\theta }\\\\tan\theta =\frac{sin\theta}{cos\theta }

Here cosec θ is the correct answer.

Option B is the correct answer.

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The time the patient expected to survive after diagnosis is 29 years.

Step-by-step explanation:

It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.

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