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Yakvenalex [24]
3 years ago
9

you deposit 200 into an account that pays 7% interest compounded quarterly. how much will you have in 5 years

Mathematics
1 answer:
scoray [572]3 years ago
8 0
First, convert R percent to r a decimal
r = R/100
r = 7%/100
r = 0.07 per year,

Then, solve our equation for A
A = P(1 + r/n)nt
A = 200.00(1 + 0.005833333/12)(12)(5)
A = $ 283.53

Summary:
The total amount accrued, principal plus interest,
from compound interest on an original principal of
$ 200.00 at a rate of 7% per year
compounded 12 times per year
over 5 years is $ 283.53.
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Mary creates a table of values for a function and plots the points. She finds that the difference in the y values is the same. W
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Answer:

Answer is: A(Linear)

Step-by-step explanation:

A linear function is a function whose graph is a straight line.

It is given that Mary plotted a graph and she found out that the difference in the y values is the same. So such a thing could happen when a function is a linear function.

since, a linear equation is given as:

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so for distinct values of x say x_{1},x_{2} we get the y-values as y_{1},y_{2}

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Hence, the function is Linear.



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Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
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