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nekit [7.7K]
3 years ago
10

Refer to the table which summarizes the results of testing for a certain disease. A test subject is randomly selected and tested

for the disease. What is the probability the subject has the disease given that the test result is negative. Round to three decimal places as needed.
Positive Test Result
Negative Test Result
Subject has the disease
87
9
Subject does not have the disease
27
312
Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

i'm guessing a positive test result

Step-by-step explanation:

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Find two consecutive integers whose sum is 95.<br><br> Let Statement(s) Equation/Solve Answer(s)
Gre4nikov [31]

47 and 48 are the integers.

Step-by-step explanation:

Let,

x and x+1 be the integers, therefore, according to statement;

x+(x+1)=95\\x+x+1=95\\2x+1=95\\2x=95-1\\2x=94\\Dividing\ both\ sides\ by\ 2\\\frac{2x}{2}=\frac{94}{2}\\x=47

2nd Integer = x+1

2nd Integer = 47+1

2nd integer = 48

47 and 48 are the integers.

Keywords: Addition

Learn more about addition at:

  • brainly.com/question/2154850
  • brainly.com/question/2367554

#LearnwithBrainly

4 0
3 years ago
If a circle has a diameter of 9 cm and circle B has a radius of 5 cm which circle has a larger circumstance in how many centimet
emmasim [6.3K]

Answer:

circle a has the larger circumstance. it is larger by 12.57 cm

5 0
3 years ago
Evaluate Expression<br> -19 + 3(-13 + 4*3)
jarptica [38.1K]

Answer:

-22

Step-by-step explanation:

Solve the expression using PEMDAS.

-19 + 3(-13 + 4 * 3)

~Multiply

-19 + 3(-13 + 12)

~Add

-19 + 3(-1)

~Multiply

-19 - 3

~Subtract

-22

Best of Luck!

3 0
2 years ago
Find the sum of the first four terms of the geometric sequence shown below. 4​, 4/ 3​, 4/9​, ...
user100 [1]
It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

S_4=4+\dfrac43+\dfrac49+\dfrac4{27}

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have

\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}

Now subtracting this from S_4 gives

S_4-\dfrac13S_4=4-\dfrac4{81}

That is, all the matching terms will cancel. Now solving for S_4, you
have

\dfrac23S_4=4\left(1-\dfrac1{81}\right)
S_4=6\left(1-\dfrac1{81}\right)
S_4=\dfrac{480}{81}=\dfrac{160}{27}
3 0
3 years ago
Joal had 5 peices of beef. He ate 3/12 of the total beef. how much beef does he have left?​
IrinaVladis [17]

Answer:

5/4

Step-by-step explanation:

5*3/12=5*1/4=5/4

3 0
3 years ago
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