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ale4655 [162]
3 years ago
14

Individuals of the same approximate weight running 6 mph or 1 mile every ten minutes have a calorie use factor of 62% of their w

eight; i.E., calories burned = (weight)(0.62). If they run an 8-minute mile, the factor is 65%. A man weighs 180 lb. He jogs a mile in 8 minutes. How many calories has he used up?
Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer: He has used up 117 calories.

Step-by-step explanation:

Given, For 62% as factor, calories burned (E)= (weight)(0.62).

Also, if they run an 8-minute mile, the factor is 65%.  [given]

Then, calories burned (E)= (weight)(0.65). [65%=0.65]

Weight of man = 180 lb

Then, calories burned (E)= 180 x (0.65).

= 117

Thus , he burned 117 calories.

So, he has used up 117 calories.

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Given that SQ¯¯¯¯¯ bisects ∠PSR and ∠SPQ≅∠SRQ, which of the following proves that PS¯¯¯¯¯≅SR¯¯¯¯¯?
yanalaym [24]

Step-by-step explanation:

It is given that ∠SPQ≅∠SRQ

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles S P Q and S R Q are highlighted in red.

It is also given that SQ⎯⎯⎯⎯⎯

bisects ∠PSR

.

By the definition of angle bisector, ∠PSQ≅∠QSR

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are congruent and highlighted in red.

△PQS

and △RQS share a common side SQ⎯⎯⎯⎯⎯, and SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

by the Reflexive Property of Congruence.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Segment S Q is highlighted in red.

Two angles, ∠SPQ

and ∠PSQ, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △PQS are congruent to two angles, ∠SRQ and ∠QSR, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △RQS

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are highlighted in red. Angles S P Q and S R Q are highlighted in red. Side S Q is highlighted in blue.

So, △PQS≅△RQS

by the Angle-Angle-Side (AAS) Congruence Theorem.

PS⎯⎯⎯⎯⎯

and SR⎯⎯⎯⎯⎯ are corresponding sides of congruent triangles, △PQS and △RQS. So, PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

by CPCTC.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Sides S R and S P are congruent and highlighted in red.

Translate these six statements and reasons into a 2

-column proof,

1. ∠SPQ≅∠SRQ

(Given)

2. SQ⎯⎯⎯⎯⎯

bisects ∠PSR

. (Given)

3. ∠PSQ≅∠QSR

(Def. of ∠

bisect)

4. SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

(Reflex. Prop. of ≅

)

5. △PQS≅△RQS

(AAS Steps 1, 3, 4)

6. PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

(CPCTC)

There you go

4 0
3 years ago
A digital gaming service offers a subscription plan with a $25 membership fee and charges a $2.50 per game rental fee. How many
erastova [34]

Answer:

They can get at most 10 games

The inequality is g=25+2.50x

Step-by-step explanation:

50=25+2.5x

50-25=25

25=2.5x

25/2.5=10

6 0
3 years ago
How many terms in <br> (3x^2-4x+2)-(2x^2-4x-5)
Drupady [299]

\text{Simplify:}\\\\(3x^2-4x+2)-(2x^2-4x-5)\\\\3x^2-4x+2-2x^2+4x+5\\\\x^2-4x+2+4x+5\\\\x^2+2+5\\\\x^2+7\\\\\boxed{\text{Two terms}}

7 0
3 years ago
Identify a pair of perpendicular segments in the diagram. PLEASE HELP!! I NEED THIS ANSWER TO RAISE MY GRADE!
Snezhnost [94]
Ab and Ae because they intersect
3 0
3 years ago
Min is about to roll a six-sided number cube. What is the experimental probability that she will roll an even number based on he
masya89 [10]

Answer:

Therefore the experimental probability that she will roll an even number is

C ) 0.5

Step-by-step explanation:

Let S be the sample space for the given experiment that to Roll six sided number Cube

∴ S ≡ { 1, 2, 3, 4, 5, 6}

∴ n(S) = 6

Let 'A' be the event of experiment that she will roll an even number

∴ A ≡ { 2, 4, 6 }

∴ n(A) = 3

To Find:

P(A) = ?

Solution:

We know that for any experiment probability is given by

\textrm{probability of the experiment}=\dfrac{\textrm{number of favourable outcomes}}{\textrm{total number of outcomes}}

Substituting the values we get

P(A)=\frac{n(A)}{n(S)} =\frac{3}{6} =\frac{1}{2} =0.5

Therefore the experimental probability that she will roll an even number is

C ) 0.5

8 0
3 years ago
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