How many terms in (3x^2-4x+2)-(2x^2-4x-5)

1 answer:

7 0

$\text{Simplify:}\\\\(3x^2-4x+2)-(2x^2-4x-5)\\\\3x^2-4x+2-2x^2+4x+5\\\\x^2-4x+2+4x+5\\\\x^2+2+5\\\\x^2+7\\\\\boxed{\text{Two terms}}$

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