Answer:192
Step-by-step explanation:
Answer:
14.50x > 85
Step-by-step explanation:
14.50x > 85
divide both sides by 14.5
x>85/14.5 = 5.86 hours
x has to be greater than 5.86 hours
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
(0,3)
Step-by-step explanation:
The parent function's vertex is at (0,0) and this function is being translated 3 units up, so the vertex is at (0,3)
