Total coins = 10 ( 4 + 3 + 3 = 10).
The probability of picking a nickel first = 4/10 = 2/5 ( 4 nickels out of 10 total).
The probability of picking a dime second = 3/9 = 1/3 ( 3 dimes out of 9 coins left).
The probability of picking the third coin as a quarter = 3/8 ( 3 quarters out of 8 coins left).
The probability of picking all three in that order = 2/5 x 1/3 x 3/8 = 1/20
Answer:
35/12 servings
Step-by-step explanation:
(7/8)/(3/10)=(7/8)(10/3)=70/24=35/12
C
Hope I helped! :-)
~Sequoyah! :-)
Answer:
so the answer would be A. 7/5x +2
if you try graphing all the other equations it would be either over the picture or just not in the right place.
