Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
There are 12 cards with different letters & patterns. The probability of randomly choosing [random card] is #[random card]/total cards.
Think of that as ratio as a %chance or probability of written as P(X). The question says to write the %chance as a fraction.
1) 2/12 = 1/6
2) 2/12 = 1/6
3) 0/12 = 0
4) 12/12 = 1
5) This is tricky. M & T would imply one card with both letters on it. 0/12 = 0
6) 4/12 = 1/3
7) 6/12 = 1/2
8) 5/12
9) 3/12 = 1/4
10) 8/12 = 2/3
11) 10/12 = 5/6
12) Odds = [favorable]:[unfavorable] = 5:7
It will be 4 o'clock when Brad takes his 16th pill.
Hope it helps
Look up range in the calculator
Answer:
82 degrees
Step-by-step explanation:
Measure of arc ABC = 86*2 = 172 degrees.
Measure of arc DC = 360 - (145+172) = 360-317 = 43 degrees.
Measure of arc BCD = 121+43 = 164 degrees.
Measure of angle A = 164/2 = 82 degrees
