Answer:
∆DEF is an isosceles ∆
Step-by-step explanation:
To find the 3 side lengths of ∆DEF, use the distance formula, which is given as .
Distance between D(-2, 3) and E(5, 5):
(nearest tenth)
Distance between E(5, 5) and F(-4, 10):
(nearest tenth)
Distance between F(-4, 10) and D(-2, 3):
(nearest tenth)
∆DEF has two equal sides, DE and FD. Therefore, ∆DEF can be classified as an isosceles triangle.
The answer would be x/4<=5
Answer:
You are right
Step-by-step explanation:
So basically find the absolute maximum of the graph that the function creates, the highest peak is the spot with the greatest y-value, in this case is (60, 1600).
The x-value that creates the greatest y is also the x-value of the vertex for that function of yours (since your function has end behavior of both ends down). To find the x-value of the vertex, get the average of the 2 x-intercepts. So (20+100)/2, which is 60.
3.47 x 20= 69.4 mm
....................
Part A:
Significant level:
<span>α = 0.05
Null and alternative hypothesis:
</span><span>h0 : μ = 3 vs h1: μ ≠ 3
Test statistics:
P-value:
P(-0.9467) = 0.1719
Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438
Conclusion:
Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.
Part B:
The power of the test is given by:
Therefore, the power of the test if </span><span>μ = 3.25 is 0.8105.
Part C:
</span>The <span>sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:
Therefore, the </span>s<span>ample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.</span>