A quotient of a number 4 at most 5

Please help me right away with both problems.

nevsk [136]

3) aₓ = 3x + 2

Plug in numbers for x (for example, 1,2,3,4).

a₁ = 3(1) + 2; a₁ = 3 + 2; a₁ = 5

a₂ = 3(2) + 2; a₂ = 6 + 2; a₂ = 8

a₃ = 3(3) + 2; a₃ = 9 + 2; a₃ = 11

a₄ = 3(4) + 2; a₄ = 12 + 2; a₄ = 14

5, 8, 11, 14, or (C) is your answer

-----------------------------------------------------------------------------------------------------------------

4) 23, 17, 11, 5

Plug in the following numbers to the equations until they match.

C) tₐ = 29 - 6n

when n = 1:

tₐ = 29 - 6(1) ; tₐ = 29 - 6 ; tₐ = 23

tₐ = 29 - 6(2) ; tₐ = 29 - 12 ; tₐ = 17

etc.

-----------------------------------------------------------------------------------------------------------------

hope this helps

8 0

3 years ago

Read 2 more answers

4.Find three consecutive integers such that the difference of double the largest number and triple the smallest number is -44. F

Taya2010 [7]

Solving a linear equation, we will see that the 3 numbers are:

48, 49, and 50.

<h3>How to find the 3 numbers?</h3>

3 consecutive integers can be written as:

x, x + 1, x + 2

Here we know that 2 times the largest number minus 3 times the smallest one is -44, then:

2*(x + 2) - 3x = -44

We can solve that linear equation for x:

2x + 4 - 3x = -44

(2 - 3)x = -44 - 4

-x = -48

x = 48

Then the 3 numbers are:

x = 48
x + 1 = 49
x + 2 = 50

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

8 0

2 years ago

160 prime factors in ascending order

igor_vitrenko [27]

I'd arbitrarily begin by writing the factors 10 and 16. These, in turn, factor to 2 and 5. That's all we need to do here to form the product 160, using 5 once and 2 several times:

160 = 5 * 2^5

4 0

4 years ago

A new neighborhood activity complex is being built in madison. the perimeter of the rectangular playing field is 268 yards. the

motikmotik

Answer:

the width is 47 yards

the length is 87 yards

Step-by-step explanation:

Given

the perimeter of the rectangular playing field is 268

perimeter of rectangle is given by 2* ( length + width)

hence for given rectangular playing field

268 = 2* ( length + width) __________________equation A

Let the width of field be W

length is seven less than double the width

Width is W then double the width will be 2*W

then 7 yards less than the double the width will be 2*W - 7

Therefore length of field in terms of W is 2*W - 7

Now substituting value of length with 2*W - 7 and

width with W in equation A, we have given below expression

268 = 2* ( 2*W - 7 + W)

=> 268/2 = 3W - 7

=> 134 = 3W - 7

=> 3W = 134 + 7 = 141

=> W = 141/3 = 47

Therefore width of rectangular playing field is 47 yards

Length of rectangular playing field = 2W - 7 = 2*47 - 7 = 94 - 7

Length of rectangular playing field = 87

Therefore Length of rectangular playing field is 87 yards

4 0

3 years ago

Complete the missing parts of the

vekshin1

Answer:

Remember the property:

a^-1 = (1/a)^1

and:

(a/b)^n = (a^n)/(b^n)

A table for a function like:

$\left[\begin{array}{ccc}x&f(x)\\&\\&\\&\\&\end{array}\right]$

Is just completed as:

$\left[\begin{array}{ccc}x&f(x)\\x_1&f(x_1)\\x_2&f(x_2)\\x_3&f(x_3)\\x_4&f(x_4)\end{array}\right]$

So, here we have:

y = f(x) = (1/6)^x

To complete the table, we need to find:

f(-1)

and

f(2)

So let's find these two values:

f(-1) = (1/6)^-1 = (6/1)^1 = 6

and the other value is:

f(2) = (1/6)^2 = 1/36

Then the complete table is:

$\left[\begin{array}{ccc}x&f(x)\\-2&36\\-1&6\\0&1\\1&1/6\\2&1/36\\1&1/216\end{array}\right]$

4 0

3 years ago