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3 years ago

What is the value of x?

Mathematics

1 answer:

Elanso [62]3 years ago

7 0

Since all the angles are congruent, the sides must be congruent too.

So, just have one equation on one side equal to another.

5x= 3x+6

Subtract 3x from both sides.

2x=6

Divide 2 into both sides.

x=3.

We can check this by seeing if all the sides are the same.

5(3)= 15

6(3)-5= 15

3(3)+6= 15

I hope this helps!
~cupcake

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3 years ago

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3 years ago

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What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Lisa [10]

Answer:

The point is P(2,7)

Step-by-step explanation:

We are given the following information in the question:

A point is located in the quadrant 1 in the following manner:

It has x-value that is 2 units from the origin.

It has a y-value 7 units from the origin.

Thus, the point is (2,7)

The attached image shows the marked point (2,7).

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3 years ago

WILL GIVE BRAINLIEST!!!!!!

Crank

Answer:

17.738

Step-by-step explanation:

to find x we’ll use sine

sin69=x/19

(remember that sine = opposite/hypotenuse)

so x = 19sin69

when typing this in your calculator you might need to change from radian to degree mode

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3 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0

3 years ago