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3 years ago

What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Mathematics

1 answer:

Lisa [10]3 years ago

4 0

Answer:

The point is P(2,7)

Step-by-step explanation:

We are given the following information in the question:

A point is located in the quadrant 1 in the following manner:

It has x-value that is 2 units from the origin.

It has a y-value 7 units from the origin.

Thus, the point is (2,7)

The attached image shows the marked point (2,7).

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Answer:

7) No

8) Yes

Step-by-step explanation:

Tangent lines are perpendicular to the radius lines at the point of intersection. So we just need to check if these are right triangles.

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2 years ago

Solve system graphically<br> y = 3x - 3<br> y = -x + 1

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Step-by-step explanation:

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3 years ago

What is the value of 10x+1 3

Veseljchak [2.6K]

SOLUTION

In this question, we are meant to expand the expression:

$(10x+1)^{3\text{ }}\text{ = ( 10 x + 1 ) (10 x + 1 ) ( 10 x + 1 )}$ $\begin{gathered} (10x+1)(10x+1)=100^{}x^2\text{ + 20 x + 1} \\ \text{Then,} \\ (100x^2+20x+1)(10x+1)=1000x^{3\text{ }}+200x^2+10x+100x^2\text{ + 20 x + 1} \\ \text{ = 1000 x}^{3\text{ }}\text{ + }300x^2\text{ + 30 x + 1} \\ \\ \text{CONCLUSION: ( 10 x + 1 )}^{3\text{ }}=1000x^{3\text{ }}+300x^2\text{ + 30 x +1} \end{gathered}$

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8 months ago

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3 years ago

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Step-by-step explanation: