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9966 [12]
3 years ago
15

What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

The point is P(2,7)

Step-by-step explanation:

We are given the following information in the question:

A point is located in the  quadrant 1 in the following manner:

It has x-value that is 2 units from the origin.

It has a y-value 7 units from the origin.

Thus, the point is (2,7)

The attached image shows the marked point (2,7).

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Identify the ellipses, represented by equations, whose eccentricities are less than 0.5
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Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

e =  \frac{c}{a}

Assuming the equations are:

\frac{ {x}^{2} }{25}  +  \frac{ {y}^{2} }{16}  = 1

Then a²=25 and b²=16

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  = 25 - 16

{c}^{2}  =  {3}^{2}

c = 3

The eccentricity is:

e =  \frac{3}{5}  = 0.6

If the ellipse has equation,

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then the this time, we have a=5 and b=3.

This means that:

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  =  {5}^{2}  -  {3}^{2}

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c = 4

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3 years ago
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What is the answer to this question?
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Step-by-step explanation:

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Step-by-step explanation:

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