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9966 [12]
3 years ago
15

What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

The point is P(2,7)

Step-by-step explanation:

We are given the following information in the question:

A point is located in the  quadrant 1 in the following manner:

It has x-value that is 2 units from the origin.

It has a y-value 7 units from the origin.

Thus, the point is (2,7)

The attached image shows the marked point (2,7).

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What is the approximate distance between the points (-2, 3, -5) and (2, -7, 4)?
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                           d = sqrt ((x2 - x1)^2 + (y2 - y1)^2 +(z2 - z1)^2)

Substituting all the data from the points given, 
                       
                    <span>d = sqrt ((2 - -2)^2 + (-7 - 3)^2 +(4 - -5)^2) = sqrt 197
</span>
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