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PSYCHO15rus [73]
3 years ago
15

Factor form

Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%20" id="TexFormula1" title=" \frac{6x { { }^{2} - 12x }^{?} }{x {}^{2} - 4 } " alt=" \frac{6x { { }^{2} - 12x }^{?} }{x {}^{2} - 4 } " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

\dfrac{6x^2-12x}{x^2-4}=\dfrac{6x(x-2)}{x^2-2^2}=\dfrac{6x(x-2)}{(x-2)(x+2)}=\dfrac{6x}{x+2}\\\\Used:\ a^2-b^2=(a-b)(a+b)

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Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot.
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Answer:

Nolan correctly identified the square  numbers before and after 18.

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