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Sonbull [250]
3 years ago
11

Suppose the null hypothesis, H0, is: Darrell has enough money in his bank account to purchase a new television. What is the Type

II error in this scenario?
Mathematics
1 answer:
seropon [69]3 years ago
3 0
<h2>Answer with explanation:</h2>

In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.

Given : Suppose the null hypothesis, H_0, is: Darrell has enough money in his bank account to purchase a new television.

Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.

i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.

You might be interested in
There are 550 people at the school carnival.
Svet_ta [14]

Answer:

70% of the people at the fair are students

165 people are on the ride

Step-by-step explanation:

In order to find a percentage, take the fraction given, 385/550, and divide the numerator, 385, and divide it by the denominator, 550. Once completing this, we get 0.7

Next, we multiply the result by 100, and get 70, thus, 385 is 70% of 550.

To find how many people 30% of 550 is, we take the percentage and put it in a fraction with the denominator being 100(changes with size of fraction like a decimal, 300 would be over a denominator of 1000)

With 30/100, we then multiply by 550 with the equation looking like this:

30/100*550/1

Once we finish multiplying(typically using a calculator, although you can do it manually) we get 165, the value of how many people are on rides out of the total 550.

4 0
3 years ago
5x-60 = -60 +2x +3x<br> how many solutions does the equation have
xeze [42]

Answer:

infinitely \: many \: solution

Step-by-step explanation:

1) Cancle -60 on both sides.

5x = 2x + 3x

2) Simplify 2x + 3x to 5x.

5x = 5x

3) Since both sides are equal, there are infinitely many solutions.

infinietly \: many \: solution

<u>Therefor</u><u>,</u><u> </u><u>this</u><u> </u><u>equation</u><u> </u><u>has</u><u> </u><u>infinitely</u><u> </u><u>many</u><u> </u><u>solutions</u><u>.</u>

5 0
3 years ago
15% of customers that come to your
Helen [10]

Answer:

Number of customers (double taco)= 45

Step-by-step explanation:

Giving the following information:

Double taco order rate= 15% = 0.15

Total number of customers= 300

<u>To calculate the number of customers that order two tacos, we need to use the following formula:</u>

Number of customers (double taco)= Double taco order rate*total number of taco

Number of customers (double taco)= 0.15*300

Number of customers (double taco)= 45

7 0
3 years ago
Solve the systems by the addition method 2x + y = - 1x - 2y = - 4
inna [77]

Answer:

x = -6/5

y =7/5

Step-by-step explanation:

2x + y = - 1

x - 2y = - 4

Multiply the first equation by 2 so we can eliminate y

2(2x + y = - 1)

4x + 2y = -2

Add this to the second equation

4x + 2y = -2

x - 2y = - 4

---------------------

5x + 0y = -6

Divide by 5

5x/5 = -6/5

x = -6/5

Multiply the second equation by -2 so we can eliminate x

-2(x - 2y = - 4)

-2x+4y = 8

Add this to the first equation

2x + y = - 1

-2x+4y = 8

---------------------

0x + 5y = 7

Divide by 5

5y/5 = 7/5

y =7/5

6 0
3 years ago
4, Find a number x such that x = 1 mod 4, x 2 mod 7, and x 5 mod 9.
olchik [2.2K]

4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.

Start with

x=7\cdot9+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 4, the last two terms vanish and we're left with

x\equiv63\equiv64-1\equiv-1\equiv3\pmod4

We have 3^2\equiv9\equiv1\pmod4, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 7, the first and last terms vanish and we're left with

x\equiv72\equiv2\pmod7

which is what we want, so no adjustments needed here.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 9, the first two terms vanish and we're left with

x\equiv140\equiv5\pmod9

so we don't need to make any adjustments here, and we end up with x=401.

By the Chinese remainder theorem, we find that any x such that

x\equiv401\pmod{4\cdot7\cdot9}\implies x\equiv149\pmod{252}

is a solution to this system, i.e. x=149+252n for any integer n, the smallest and positive of which is 149.

3 0
3 years ago
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