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Naya [18.7K]
3 years ago
13

Ramona believes that plants exposed to radio waves will become extra tall. She decides to plant two

Mathematics
1 answer:
Anika [276]3 years ago
6 0

Answer:I have this same problem but if you’re asking for the independent and other questions here’s the answer. Independent variable is the radio since that’s the only change happening to the 10 other pots. Dependent variable is the height of the plant since that’s what Ramona wants to see change as the output. Control group is the 5 pots without the radio i’m pretty sure. The constants are the amount of seeds, pots, soil, and water.

Step-by-step explanation:

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How to solve (x+8) (x+6)
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Multiply each throughout!
=x^2+6x+8x+48
then arrange accordingly
x^2+14x+48
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What is the measure of ∠R?
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Angle R= 36°

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Find the m of
zzz [600]

          Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.

[23] ABD = 42°, DBC = 35°

(4x - 2) + (3x + 2) = 77°

4x+ 3x + 2 - 2  = 77°

4x+ 3x= 77°

7x= 77°

x= 11°

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ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°

DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°

[24] ABD = 62°, DBC = 78°

(4x - 8) + (4x + 8) = 140°

4x + 4x + 8 - 8 = 140°

4x + 4x = 140°

8x = 140°

8x = 140°

x = 17.5°

-

ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°

DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°

6 0
1 year ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below.
Vikentia [17]

Answer:

Given Polynomial:

80b^4-32b^2c^3+48b^4c

Factors of Coefficient of terms

80 = 5 × 16

32 = 2 × 16

48 = 3 × 16

Common factor of the coefficient of all term is 16.

Each term contain variable. So the Minimum power of b is common from all terms.

Common from all variable part comes b².

So, Common factor of the polynomial = 16b²

⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )

⇒ 16b² ( 5b² - 2c³ + 3b²c )

Therefore, Statements that are true about David's word are:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property

8 0
3 years ago
Read 2 more answers
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