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Blababa [14]
3 years ago
13

Whats the answer plzz answer for me

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
1. 958-236=722 
2. 878-247=631
3. 998-346= 652
4. 967-323= 644
5. 998-353= 645
6.876-322= 554
7.948-526= 422
8.968-353=615
9. 798-363= 435
10. 978-735= 243
11. 693-572= 121
12. 867-432= 435
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Yuri [45]

Answer:

X = {8n – 7n – 1 : n ϵ N}

Y = {49 (n –1) : n ϵ N} — (1) [all terms divisible by 49]

X = {8n – 7n – 1}

= (1 + 7)n – 7n – 1

= 1 + nC1 7 + nC2 72 + ….. + nCn 7n – 7n – 1

= nC2 72 + …… + nCn 7n

= 49 [nC2 + nC3 7 + …. nCn 7n-2] — (2)

From (1) and (2),

X is divisible by 49.

Y has all multiples of 49.

X ⊂ Y

6 0
2 years ago
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The escalator rises 25 degrees from the ground and a vertical distance of 42 ft. How much horizontal distance does the escalator
Galina-37 [17]
67 ft (rounded is 70 ft)
5 0
4 years ago
20 POINTS!!!!!! SOLVE FOR X​
WITCHER [35]

Answer:

All you have to do is equal the equations to each other to find x for each problem!

Step-by-step explanation:

Hope this helps bestieee!

8 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIST
sdas [7]

Answer:

Its hard to explain but essentially the zero in the 10 and 100 place cancels out the decimal essentially

8 0
3 years ago
Find the coordinates of the point which divides the join of (-1,7) and (4.-3) in the ratio 2:3 ??
d1i1m1o1n [39]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h2>

Find the coordinates of the point which divides the join of (-1,7) and (4,-3) in the ratio 2:3 ?

<h2><u>Solution</u>:-</h2>

Let the given points be A(-1,7) and B(4,-3)

Now,

Let the point be P(x, y) which divides AB in the ratio 2:3

Here,

<h3>{ \bf  x \: = \frac{m_1 x_2 \: + \: m_1 x_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = -1 , x_2 = 4

\therefore Putting values we get,

x = \frac{2 \: × \: 4 \: + \: 3 \: × \: -1}{2 \: + \: 3}

x = \frac{8 \: - \: 3}{5}

x = \frac{5}{5}

x = 1

Now,

Finding y

<h3>{ \bf  y \: = \frac{m_1 y_2 \: + \: m_2 y_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = 7 , x_2 = -3

\therefore Putting values we get,

y = \frac{2 \: × \: -3 \: + \: 3 \: × \: 7}{2 \: + \: 3}

y = \frac{-6 \: + \: 21}{5}

y = \frac{15}{5}

y = 3

Hence x = 1, y = 3

So, the required point is P(x, y)

= P(1, 3)

<h3>The coordinates of the point is P(1, 3). [Answer]</h3>

_______________________________________

<u>N</u><u>o</u><u>t</u><u>e</u>:- Refer the attachment.

_______________________________________

5 0
3 years ago
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