All categories

3 years ago

Logan dug a hole 5/6 feet deep.michael dug a hole 1/4 feet deep.how much deeper is logans hole than michael

Mathematics

2 answers:

Simora [160]3 years ago

8 0

Answer:

7/12 feet

Step-by-step explanation:

5/6 - 1/4

LCD is 12... 10/12 - 3/12 = 7/12

shtirl [24]3 years ago

7 0

7/12 ft. Basically it’s 5/6-1/4 to get 7/12 (I did 20/24-6/24 to get 14/24 and simplified to 7/12)

You might be interested in

2-7x-3x=-8x-8 Explain Thanks

Agata [3.3K]

$2-7x-3x=-8x-8\\\\-7x-3x+8x=-8-2\\\\-2x=-10 \ \ /:(-2)\\\\\huge\boxed{x=5}$

4 0

2 years ago

Read 2 more answers

A company introduces a new product for which the number of units sold S is

KonstantinChe [14]

(a) The "average value" of a function over an interval [a,b] is defined to be

(1/(b-a)) times the integral of f from the limits x= a to x = b.

Now S = 200(5 - 9/(2+t))

The average value of S during the first year (from t = 0 months to t = 12 months) is then:

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12

This equals 200/12 * (5t -9ln(2+t))

Evaluating this with the limits t= 0 to t = 12 gives:

708.113 units., which is the average value of S(t) during the first year.

(b). We need to find S'(t), and then equate this with the average value.

Now S'(t) = 1800/(t+2)^2

So you're left with solving 1800/(t+2)^2 = 708.113

I'll leave that to you

6 0

2 years ago

The graphs of two functions are shown.

Naily [24]

Range, Maximum, and y-intercept

3 0

3 years ago

Read 2 more answers

Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred

Ksivusya [100]

1. $m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}$ , then $m\angle ABC=m\angle ACD$ and triangles ADC and ACB are similar by AAA theorem.

2. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{AC}{AB}= \dfrac{AD}{AC}$ .

3. Knowing lengths you could state that $\dfrac{b}{c}= \dfrac{e}{b}$ .

4. This ratio is equivalent to $b^2=ce$ .

5. $m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}$ , then $m\angle BAC=m\angle BCD$ and triangles BDC and BCA are similar by AAA theorem.

6. The ratio of the corresponding sides of similar triangles is constant, so

$\dfrac{BC}{BD}= \dfrac{AB}{BC}$ .

7. Knowing lengths you could state that $\dfrac{a}{d}= \dfrac{c}{a}$ .

8. This ratio is equivalent to $a^2=cd$ .

9. Now add results of parts 4 and 8:

$b^2+a^2=ce+cd$ .

10. c is common factor, then:

$b^2+a^2=c(e+d)$ .

11. Since $e+d=c$ you have $a^2+b^2=c\cdot c=c^2$ .

7 0

3 years ago

Read 2 more answers

Twelve more than half of a number is equal to the number

tester [92]

Let's consider that number to be 'x'..
So, twice the number (2x) is 12 greater than than the half of the number.
So the equation will be like,
2x=12+x/2
Solving this further,
2x=(24+x)/2
=> 4x=24+x
=>4x-x=24
=>3x=24
=>x=8..
So the number is "8".

5 0

2 years ago