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enot [183]
3 years ago
7

Solve the system. x+y=5 -2x+4y=8 A. (1,4) B. (5,1) C. (2,3) D. (5,1)

Mathematics
1 answer:
aksik [14]3 years ago
7 0
The answer is c
2 + 3 = 5

-2 (2) + 4 (3) = 8
-4 + 12 = 8
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What is number 3 please explain for brainlest answer !! :))
Phoenix [80]

Answer:

The answer is B) 1/25

Step-by-step explanation:

This is because given that f(x) = 5^x

Hence, f(-2) would be 5^-2, which is equal to (1/5^2) => 1/25

Because a^-b can be written as 1/a^b

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Consider the three scatterplots labeled I, II, and III. Which set of data shows the greatest correlation coefficient?
lyudmila [28]

Answer:

D) All three have the same correlation coefficient.

8 0
3 years ago
Help as soon as possible pleaseee
KiRa [710]

Answer:

(3x + 2)(x-4)

Step-by-step explanation:

3x² - 10x - 8 = 0

(splitting the middle term)

3x² -12x + 2x -8 = 0

3x(x-4) + 2(x-4) = 0

(3x + 2)(x-4) = 0

(3x + 2)(x-4) is the correct answer (option a)

3 0
3 years ago
Read 2 more answers
Points H and F lie on circle c What is the length of line segment GH?
Nina [5.8K]

Answer:

6 units

Step-by-step explanation:

Given: Points H and F lie on  circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.

To find: Length of GH.

Sol: EC = CH = 9 (Radius of the same circle are equal)

Now, GC = GH + CH

GC = GH + 9

Now In ΔEGC, using pythagoras theorem,

(Hypotenuse)^{2} = (Base)^{2} +(Altitude)^{2} ......(ΔEGC is a right triangle)

(GC)^{2} = (GE)^{2} +(EC)^{2}

(GH + 9)^{2} = (9)^{2} +(12)^{2}

(GH )^{2} + (9)^{2} + 18GH = 81 + 144

(GH )^{2} + 81 + 18GH = 81 + 144

(GH )^{2} + 18GH = 144

Now, Let GH = <em>x</em>

x^{2} +18x = 144

On rearranging,

x^{2} +18 x - 144 = 0

x^{2} - 6x +24x + 144 = 0

x (x-6) + 24 (x - 6) =0

(x - 6) (x + 24) = 0

So x = 6  and x = - 24

∵ x cannot be - 24 as it will not satisfy the property of right triangle.

Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.

3 0
3 years ago
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A customer deposits $500 in an account that pays 5% annual interest.
skelet666 [1.2K]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$500\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases} \\\\\\ A=500\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies A=500(1.05)^3\implies A\approx 578.81

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2 years ago
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