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SIZIF [17.4K]
3 years ago
15

Double-Angle and Half-Angle Identiies [See Attachment] Question 4

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0
Please make it brainleist

Sati [7]3 years ago
5 0

We have


\sin 2 \theta = 2 \sin \theta \cos \theta


We already know \sin \theta so we have to find \cos \theta.


Theta is in the first quadrant so we choose the positive sign:


\cos \theta = \sqrt{1 - (2/5)^2} = \sqrt{21/25} = \frac 1 5\sqrt{21}


\sin 2 \theta = 2 (\frac 2 5)(\frac 1 5 \sqrt{21}) = \dfrac{4 \sqrt{21}}{25}


Choice c


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Answer:

175\ in^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

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y----> volume of the smaller solid

z^{3}=\frac{x}{y}

we have

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substitute

z^{3}=\frac{125}{27}

z=\frac{5}{3}

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

z^{2}=\frac{x}{y}

we have

z=\frac{5}{3}

y=63\ in^{2}

substitute

(\frac{5}{3})^{2}=\frac{x}{63}

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3 years ago
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Answer:

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Step-by-step explanation:

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