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SIZIF [17.4K]
3 years ago
15

Double-Angle and Half-Angle Identiies [See Attachment] Question 4

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0
Please make it brainleist

Sati [7]3 years ago
5 0

We have


\sin 2 \theta = 2 \sin \theta \cos \theta


We already know \sin \theta so we have to find \cos \theta.


Theta is in the first quadrant so we choose the positive sign:


\cos \theta = \sqrt{1 - (2/5)^2} = \sqrt{21/25} = \frac 1 5\sqrt{21}


\sin 2 \theta = 2 (\frac 2 5)(\frac 1 5 \sqrt{21}) = \dfrac{4 \sqrt{21}}{25}


Choice c


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4. Stella says the equation x^2−8x+y^2+2y=5 has a center of (4,−1) and a radius of 5. Is she correct? Why or why not?
Ostrovityanka [42]
<h2>Stella is correct about center and wrong about radius      </h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

          (x-h)²+(y-k)² = r²

Here equation is

          x²−8x+y²+2y=5

Changing in to (x-h)²+(y-k)² = r² form

           x²−8x + 16 - 16 +y²+2y+1 - 1=5  

           (x-4)² - 16 + (y+1)² -1 = 5

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           (x-4)²  + (y+1)²  = 4.69²

           Center is (4,-1) and radius is 4.69

Stella is correct about center and wrong about radius            

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What is the value of x in the equation below?
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