Answer:
-3x+3
Step-by-step explanation:
The equation to the line shown is formed as follows.
It passes through the points (-6,0) and (-8,6)
The gradient of the line=Δy/Δx
=(y₂-y₁)/(x₂-x₁)
=(6-0)/(-8--6)
=6/-2
=-3
The line parallel to the line shown has the same gradient i.e -3
Therefore the line in question is
-3x+3.
80 because 160 divided by 2 is 80 so 2 x 80
Answer:
Step-by-step explanation:
Find c if ∠PQR = 90°?
I will ASSUME you mean point P is at (3. c)
slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6
slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)
perpendicular lines have negative reciprocal slopes.
(2 - c) / 6 = -1(3c - 9)/9
9(2 - c) = -6(3c - 9)
18 - 9c = -18c + 54
9c = 36
c = 4
Answer:
Inverse property of multiplication
