What is 900 / y = 50 nwividsjvksfnvkjsjvcjsjvsajijviajsnjsikfjvinsjgksjvkksnvksafojbknfbnajdsvnjfdjvjvndj

A saleswoman earns 3% commission on all the merchandise that she sells. Last month she sold $3000 worth of merchandise. How much

Lynna [10]

She earned $90 commission last month.

Step-by-step explanation:

Given,

Commission rate of saleswoman = 3%

Sold worth of merchandise = $3000

Commission amount = 3% of sold worth

$Commission\ amount=\frac{3}{100}*3000\\\\Commission\ amount=\frac{9000}{100}\\\\Commission\ amount=\$90$

She earned $90 commission last month.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

4 0

3 years ago

E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best cha

Sliva [168]

The difference between the first company and the other is that the first charges $1 less per movie than the second , but charges $15 more than the second as well.
To awnser this problem and equal the charges in bth companies we just need to cancel out the $15 the first company charges more than the second.
As we pay more $1 each movie in the first , we would need to view 15 movies to equalize the charges from both companies :
x= 15 if we want to equalize the charges

f(x) = 4.95(15) + 40
f(x) = 74.25 + 40 = 114.25

g(x) = 5.95(15) + 25
g(x) = 89.25 + 25 = 114.25

Awnser: We would need to view 15 pay per view to equalize the bills from both companies

6 0

3 years ago

Read 2 more answers

If it is a tree then it has leaves which of the diagrams below represents the statement

AysviL [449]

Answer: B

Step-by-step explanation:

7 0

3 years ago

Calculus. Please answer question attached.

quester [9]

(a) Given $f(x) = x^3$ , the derivative is

$f'(x)=3x^2$

which is exists for all $x$ in the domain of $f$ , so $]f$ is differentiable everywhere and satisfies the mean value theorem. There is some number $c$ in the open interval (0, 2) such that

$f'(c) = \dfrac{f(2) - f(0)}{2-0} \iff 3c^2 = \dfrac{8-0}2 = 4$

Solve for $c$ :

$3c^2 = 4 \implies c^2 = \dfrac43 \implies \boxed{c = \dfrac2{\sqrt3}}$

We omit the negative square root since it doesn't belong to (0, 2). Graphically, the MVT tells us the tangent line to the curve $f(x)=x^3$ at $x=\frac2{\sqrt3}$ is parallel to the secant line through the endpoints of the given interval.