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gayaneshka [121]
3 years ago
8

Find the indicated variables

Mathematics
1 answer:
juin [17]3 years ago
8 0
A-60
B-19
C-101
D-79
E-50
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y=2x^2-4\ \ \ |+4\\\\2x^2=y+4\ \ \ |:2\\\\x^2=\dfrac{y+4}{2}\\\\x=\sqrt{\dfrac{y+4}{2}}

y^{-1}=\sqrt{\dfrac{x+4}{2}}=\dfrac{\sqrt{x+4}}{\sqrt2}=\dfrac{\sqrt{2(x+4)}}{2}=\dfrac{\sqrt{2x+8}}{2}
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I need help with this question
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Answer:

Tax~required~to~be~paid = 5.4%  (5) = \frac{5.4}{100}(5) = \frac{27}{100}~of~(5) = \frac{5.4}{100}(5) = \frac{27}{100} = 0.27~dollars

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A semi-circle window can be used above a doorway or as an accent window
anzhelika [568]

A semicircle is a part of a circle, and it is referred to as half of a given circle. Thud the area of the <em>semi-circle</em> window is 982 in^{2}.

A circle is a shape that is <u>bounded</u> by a <em>curved</em> path which is referred to as the <em>circumference</em>. Some <u>parts</u> of a circle are radius, diameter, sector, arc, semi-circle, circumference, etc.

A <em>semicircle</em> is a <u>part</u> of a <u>circle</u>, and it is referred to as <em>half </em>of a given <em>circle</em>.

such that:

<em>Area</em> of a <u>circle</u> = \pi r^{2}

and

area of a <u>semicircle</u> = \frac{\pi r^{2} }{2}

where: r is the <u>radius </u>of the <u>circle</u>, and \pi is a <u>constant </u>with a value of \frac{22}{7}.

Thus from the given question, it can be inferred that;

r = \frac{50}{2}

 = 25

r = 25 in

Thus, the area of the<em> semi-circle</em> can be determined as;

area of the <em>semi-circle</em> = \frac{1}{2} * \frac{22}{7} * 25^{2}

                                      = 982.1429

area of the semi-circle = 982.14 in^{2}

The area of the <em>semi-circle</em> window is approximately 982 in^{2}.

for more clarifications on the area of a semi-circle, visit: brainly.com/question/15937849

#SPJ 1

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