There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
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We have the area of the base of a triangular prism= a*b
the volume of triangular prism =a*b*c( where c is the height) so that 210=a*b*14 ==> 210= base area*14==> base area= 210/14
Answer:
2 x^4
Step-by-step explanation:
Recall that the GCF is the greatest of the product of factors that are common to all these three expressions
then for the pure numerical part, the factor common to 50, -10 , and 2 is "2"
and for the variable part x^4 is the largest common to all three expressions.
Therefore the GCF is: 2 x^4
3x + 6 = -1 - 3 + 4x
Combine like terms on the right side.
3x + 6 = -4 + 4x
Add 4 to both sides.
3x + 10 = 4x
Subtract 3x from both sides.
10 = x
The equation has one solution (10).
Answer: The answer is <em><u>-2</u></em>
Step-by-step explanation:
that is where the line starts
hope this helped