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professor190 [17]
3 years ago
9

4. A is an algebraic expression made by adding or subtracting terms.

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

You have one algebraic expression. It can be simplified by adding and subtracting like terms within it.

You have two algebraic expressions and are asked to add or subtract them. After adding or subtracting, you’ll end with one final algebraic expression.

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Anna71 [15]

Answer:

$9.50

Step-by-step explanation:

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3 years ago
The function f(x) is shown in this graph.
Sladkaya [172]
The function f(x) goes down by two and over by one:
slope = rise/run = -2/1 = -2.

The slope of f(x) is -2, while the slope of g(x) is -6.

Since -2 is a greater number than -6, the answer is:
C) <span>The slope of f(x) is greater than the slope of g(x). </span>
6 0
3 years ago
Read 2 more answers
What is the best estimate for the length of an ant's leg? *
Novosadov [1.4K]

Answer: about 1 cm

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5 0
2 years ago
Please help!!! 20 points
V125BC [204]

Answer:

A) x = (-8log(6)-2log(17))/(-2log(17)+log(6))

Step-by-step explanation:

Taking the logarithm of the equation, you have ...

(x+8)log(6) = (2x-2)log(17)

Subtracting the right side from the equation gives ...

x(log(6) -2log(17)) +8log(6)+2log(17) = 0

Subtracting the constant and dividing by the coefficient of x gives ...

x = -(8log(6) +2log(17))/(log(6) -2log(17)) . . . . . matches selection A

___

You don't need to work out the whole solution to determine the correct answer choice. Once you take the initial log, you find that the x-coefficient includes a multiplier of 2log(17). This term only appears in the denominator of choice A. (The value of x will be found after dividing by the x-coefficient, so you know this must show up in the denominator of the answer.)

6 0
3 years ago
Simplify.<br> <img src="https://tex.z-dn.net/?f=%5Csqrt32%20%2B%20%5Csqrt16%2B%20%5Csqrt8" id="TexFormula1" title="\sqrt32 + \sq
svetoff [14.1K]

Answer:

4 + 6 \sqrt{2}

Step-by-step explanation:

\sqrt{32}  +  \sqrt{16}  +  \sqrt{8}

\sqrt{32}  =  \sqrt{4 \times 4 \times 2}  =  4\sqrt{2}

\sqrt{16}  =  \sqrt{4 \times 4}  = 4

\sqrt{8}  =  \sqrt{2 \times 2 \times 2}  = 2 \sqrt{2}

4 +  4\sqrt{2}  + 2 \sqrt{2}  = 4 + 6 \sqrt{2}

5 0
2 years ago
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