Solve this problem as quickly as you can

For each equation, determine whether it represents a direct variation, an inverse variation, or neither.

icang [17]

For the first question which is y=x/3, here as we see that both are in top. So they represents direct variation and constant of variation is 1/3 .

For the second question , which is 6/y=x, y is denominator and x is in the denominator. So they represents inverse variation and the constant of proportionality is 6 here .

5 0

4 years ago

The cost of 24 peincle is 4.08 find the price in filler per peincle

choli [55]

.17 i believe by doing 4.08/24

8 0

4 years ago

As shown at the right, rectangle abcd has vertices c and d on the. V-axis and vertices a and b on the part of the parabola y — 9

Sergio039 [100]

a) The <em>perimeter</em> function of the rectangle is $p = 18\cdot x -2\cdot x^{3}$ .

b) The domain of the <em>perimeter </em>function is $x \in [-3, 3]$ .

<h3>How to analysis the perimeter formula of a rectangle inside a parabola</h3>

a) The perimeter of a rectangle ( $p$ ) is the sum of the lengths of its four sides:

$p = AB\cdot AC$ (1)

If we know that $AB = 2\cdot x$ and $AC = 9-x^{2}$ , then the perimeter of the rectangle is represented by the following formula:

$p = 2\cdot x \cdot (9-x^{2})$

$p = 18\cdot x -2\cdot x^{3}$

The <em>perimeter</em> function of the rectangle is $p = 18\cdot x -2\cdot x^{3}$ . $\blacksquare$

b) The domain of the function is the set of values of $x$ associated to the function. After a quick inspection, we find that the domain of the <em>perimeter </em>function is $x \in [-3, 3]$ . $\blacksquare$

<h3>Remark</h3>

The statement is incomplete and poorly formatted. The correct form is described below:

<em>As shown at the right, rectangle ABCD has vertices C and D on the x-axis and vertices A and B on the part of the parabola </em> $y = 9-x^{2}$ <em> that is above the x-axis. a) Express the perimeter </em> $p$ <em> of the rectangle as a function of the x-coordinate of A. b) What is the domain of the perimeter function?</em>