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Arlecino [84]
4 years ago
13

Convert 16 cm/hr to m/min

Mathematics
1 answer:
jeyben [28]4 years ago
7 0

<u><em>0.00266666667</em></u> m / min.

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Plz help with number's 1,2,3 thx!
VARVARA [1.3K]
1.) B
2.) C
3.) D

those are the answers
I'd triple checked it :)
6 0
3 years ago
Tara models an addition problem using five red tiles and seven blue tiles. What is the final sum for this problem?
son4ous [18]
The answer is 2 because the blue tiles (7) have more then the red tiles (5).
4 0
3 years ago
I need a answer soon please!
Evgesh-ka [11]

Answer:

Let there were total x people at the conference

so 32%of x is 216

32/100×x=216

x=216×100/32

x=675

So total people present at the conference were 675

8 0
3 years ago
Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e
netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

F(x)=\frac{e^x-1-x}{x^2}

When,

x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281

x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885

x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091

x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438

x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)

Correct upto six decimal places.

Now,

\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}   (\frac{0}{0}) form, applying L-Hospital rule that is differentiating numerator and denominator we get,

\lim_{x\to 0}F(x)

=\lim_{x\to 0}\frac{e^x-1}{2x}    (\frac{0}{0}) form.

=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).  

8 0
3 years ago
Figure
ludmilkaskok [199]

Answer:

  • a rotation, followed by a translation
  • a translation, followed by two reflections

Step-by-step explanation:

The rigid motions are the transformations that produce congruent images.

There are three main kinds of rigid motions  :

  • Reflections : Flips a figure across a line of reflection.
  • Rotations : Rotates a figure about some degrees around a center point.
  • Translations : Moves figure on a plane about some distance in a certain direction.

But dilation is not a rigid transformation because it may change the size of the image. It is usually used to shrink or enlarge a shape.

So, the options having dilation and term "stretch" cannot produce congruent figures.

Hence, the correct options are :

  • a rotation, followed by a translation
  • a translation, followed by two reflections
5 0
3 years ago
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