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Tamiku [17]
3 years ago
14

Which graph represents the solution set for the system 6x + y > -3 and 2x + y ≤ 4?

Mathematics
1 answer:
givi [52]3 years ago
7 0
Graph B is the correct answer
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Need help anyone can help
Ket [755]

Answer:

b

Step-by-step explanation:

because

7 0
2 years ago
7 - 14x = 2x - 5<br> This is hard
gizmo_the_mogwai [7]

Answer:

3/4 = x

Step-by-step explanation:

7 - 14x = 2x - 5

+14x    +14x

_____________

7 =16x -5

+5     +5

__________-

12 = 16x

÷16   ÷16

__________

12/16 = x

-or-

3/4 = x

Hope this helped :D

6 0
3 years ago
Read 2 more answers
without building the graph, find the coordinates of the point of intersection of the lines given by the equation y=3x-1 and 3x+y
DaniilM [7]
<h2><u>1. Determining the value of x and y:</u></h2>

Given equation(s):

  • y = 3x - 1
  • 3x + y = -7

To determine the point of intersection given by the two equations, it is required to know the x-value and the y-value of both equations. We can solve for the x and y variables through two methods.

<h3 /><h3><u>Method-1: Substitution method</u></h3>

Given value of the y-variable: 3x - 1

Substitute the given value of the y-variable into the second equation to determine the value of the x-variable.

\implies 3x + y = -7

\implies3x + (3x - 1) = -7

\implies3x + 3x - 1 = -7

Combine like terms as needed;

\implies 3x + 3x - 1 = -7

\implies 6x - 1 = -7

Add 1 to both sides of the equation;

\implies 6x - 1 + 1 = -7 + 1

\implies 6x = -6

Divide 6 to both sides of the equation;

\implies \dfrac{6x}{6}  = \dfrac{-6}{6}

\implies x = -1

Now, substitute the value of the x-variable into the expression that is equivalent to the y-variable.

\implies y = 3(-1) - 1

\implies     \ \ = -3 - 1

\implies     = -4

Therefore, the value(s) of the x-variable and the y-variable are;

\boxed{x = -1}   \boxed{y = -4}

<h3 /><h3><u>Method 2: System of equations</u></h3>

Convert the equations into slope intercept form;

\implies\left \{ {{y = 3x - 1} \atop {3x + y = -7}} \right.

\implies \left \{ {{y = 3x - 1} \atop {y = -3x - 7}} \right.

Clearly, we can see that "y" is isolated in both equations. Therefore, we can subtract the second equation from the first equation.

\implies \left \{ {{y = 3x - 1 } \atop {- (y = -3x - 7)}} \right.

\implies \left \{ {{y = 3x - 1} \atop {-y = 3x + 7}} \right.

Now, we can cancel the "y-variable" as y - y is 0 and combine the equations into one equation by adding 3x to 3x and 7 to -1.

\implies\left \{ {{y = 3x - 1} \atop {-y = 3x + 7}} \right.

\implies 0 = (6x) + (6)

\implies0 = 6x + 6

This problem is now an algebraic problem. Isolate "x" to determine its value.

\implies 0 - 6 = 6x + 6 - 6

\implies -6 = 6x

\implies -1 = x

Like done in method 1, substitute the value of x into the first equation to determine the value of y.

\implies y = 3(-1) - 1

\implies y = -3 - 1

\implies y = -4

Therefore, the value(s) of the x-variable and the y-variable are;

\boxed{x = -1}   \boxed{y = -4}

<h2><u>2. Determining the intersection point;</u></h2>

The point on a coordinate plane is expressed as (x, y). Simply substitute the values of x and y to determine the intersection point given by the equations.

⇒ (x, y) ⇒ (-1, -4)

Therefore, the point of intersection is (-1, -4).

<h3>Graph:</h3>

5 0
2 years ago
What is sociallizatioj​
Tresset [83]

Answer:

Socialisation is the process through which individuals learn the norms and values of society, leading to social cohesion and a functional society

hope it helps you

please mark me as brainlist

8 0
3 years ago
Read 2 more answers
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about the origin, (0,0). y 71 c 3+ 2+ 2 1 2 3 4 5 6 7
VLD [36.1K]

Answer:

give me the bubble bubble I really do not know

7 0
2 years ago
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