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miskamm [114]
3 years ago
13

You decide to put $2,000 in a savings account to save for a $3,000 downpayment on a new car. If the account has an interest rate

of 4% per year and is compounded monthly, how long does it take until you have $3,000 without depositing any additional funds?
121.862 years
12.1862 years
10.155 years
1.0155 years
Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0

It takes 10.155 years until you have $3,000 ⇒ 3rd

Step-by-step explanation:

The formula for compound interest, including principal sum is:

A=P(1+\frac{r}{n})^{nt} , where

  • A is the future value of the investment/loan, including interest
  • P is the principal investment amount  
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

∵ You decide to put $2,000 in a savings account

∴ P = 2000

∵ You want to save for $3,000

∴ A = 3000

∵ The account has an interest rate of 4% per year and is

   compounded monthly

∴ r = 4% = 4 ÷ 100 = 0.04

∴ n = 12 ⇒ compounded monthly

- Substitute all of these values in the formula above to find t

∵ 3000=2000(1+\frac{0.04}{12})^{12t}

- Divide both sides by 2000

∴ 1.5=(1+\frac{1}{300})^{12t}

∴ 1.5=(1\frac{1}{300})^{12t}

- Change the mixed number to an improper fraction

∴ (1.5)=(\frac{301}{300})^{12t}

- Insert ㏒ for both sides

∴ log(1.5)=log(\frac{301}{300})^{12t}

- Remember log(a)^{n}=nlog(a)

∴ log(1.5)=(12t)log(\frac{301}{300})

- Divide both sides by log(\frac{301}{300})

∴ 121.84 = 12 t

- Divide both sides by 12

∴ 10.155 = t

It takes 10.155 years until you have $3,000

Learn more:

You can learn more about the compound interest in brainly.com/question/4361464

#LearnwithBrainly

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Oliga [24]

Answer:

<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>

Step-by-step explanation:

Givens

  • Max has $5.50.
  • He has eight more quarters than he does nickels.
  • He had four times as many dimes as he has nickels.

From these statements, we can deduce algebraical expressions to solve the problem. Let's call q quarters, n nickels and d dimes.

q=n+8 (8 more quarters than nickels)

d=4n (he has four times as many dimes as he has nickels).

0.25q+0.05n+0.10d=5.50 (Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).

Let's replace the first two expressions into the third equation

0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5

There are 5 nickels.

Now, we use this value to find the number of quarters

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There are 13 quarters.

Also, d=4(5)=20

There are 20 dimes.

Therefore, there are 13 quarters, 5 nickels and 20 dimes.

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Hope it helps!

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