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Temka [501]
2 years ago
13

1) What is the area of square of length 5cm?

Mathematics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

20 is my answer and the question is somehow confusing

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Solve for v.<br> -8v+3(v-3) = 16
puteri [66]

Hi there! :)

Answer:

\huge\boxed{v = -5}

-8v + 3(v - 3) = 16

Distribute the 3:

-8v + 3(v) + 3(-3) = 16

-8v + 3v - 9 = 16

Combine like terms and simplify:

-5v - 9 = 16

-5v - 9 + 9 = 16 + 9

-5v = 25

Divide both sides by -5:

-5v/(-5) = 25/(-5)

v = -5.

7 0
3 years ago
Read 2 more answers
Find the missing length indicated. Leave your answer in simplest radical form.
pickupchik [31]
25

The triangle given by 9, unknown, and 15 and the triangle given by 15, unknown, and x are similar triangles and therefore 9:15 = 15:x

X is 25 in this case
8 0
3 years ago
If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
mihalych1998 [28]
Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
4 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
I need help!!!! Evaluate 4/7 + 8/3 in fraction form
Reptile [31]

Answer:

  • 3 5/21.
  • 68/21

Step-by-step explanation:

<u>Given equation:</u>

  • 4/7 + 8/3

<u>Solve:</u>

  • 4/7 + 8/3
  • = 12/21 + 56/21
  • = \frac{12 + 56}{21 + 0}
  • = 3 5/21.
  • = 68/21.
8 0
2 years ago
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