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lara [203]
2 years ago
10

Help What is the graph???

Mathematics
1 answer:
marin [14]2 years ago
6 0

We are given

y=\frac{x^2-4x+3}{x^2-9}

Vertical asymptotes:

Firstly, we will factor numerator and denominator

we get

y=\frac{(x-1)(x-3)}{(x-3)(x+3)}

We can see that (x-3) is common in both numerator and denominator

so, we will only set x+3 to 0

and then we can find vertical asymptote

x+3=0

x=-3

Hole:

We can see that (x-3) is common in both numerator and denominator

so, hole will be at x-3=0

x=3

Horizontal asymptote:

We can see that degree of numerator is 2

degree of denominator is also 2

for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator

and we get

y=1

now, we can draw graph

Graph:


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3 years ago
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5 0
3 years ago
Can you please help me with this problem?
Hoochie [10]
Here you have to find which each variable is, for this you start of picking one equation,

x + 2y + 6z = 4
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4x + 2z = 16

depending the equation you pick you multiply that by a certain number that will give you the opposite of one of the other equations,
-1(x + 2y + 6z = 4)
= -x -2y - 6z = -4

With this you add or subtract it with the equation that has the same number or variable, or both,
In this case it will be the equation,
-3x + 2y + 6z = 4
You can use this one or the third equation since both have a positive 2y which will cancel with -2y from the new equation,
-x - 2y - 6z = -4
-3x + 2y -z = -4

= -4x -7z = -8
Now you since you just eliminated the variable (y) you now have 2 variables, and the last equation has only 2 variables, meaning now you find the answer to those to equations,

-4x -7z = -8
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Now leave the variable by itself,
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6 0
2 years ago
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