Find the equation of a line that has a slope of -3/2 and passes through the point (2,1)
2 answers:
Answer: 4
Step-by-step explanation:
y = -3/2 x + 4
Step-by-step explanation:
y - y1 = m(x - x1)
Here, m = slope = -3/2 & (x1,x2) = (2, 1)
=> y - 1 = (-3/2) (x - 2)
=> y - 1 = -3/2 x + 3
=> y = - 3/2 x + 3 + 1
=> y = -3/2 x + 4
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