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2 years ago

HELP!!!..........................................

Mathematics

1 answer:

geniusboy [140]2 years ago

7 0

Answer:

A.) the function is increasing on the interval (-∞, 0) and decreasing on interval (0,∞)

Step-by-step explanation:

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Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

2 years ago

A company has actual unit demand for four consecutive years of 100, 105, 135, and 150. The respective forecasts were 120 for all

Lubov Fominskaja [6]

Answer:

c. 20

Step-by-step explanation:

Calculation to determine Which of the following is the resulting MAD value that can be computed from this data

Using this formula

MAD= [ABS( Year 1 actual unit demand - Forecast) + ABS (Year 2 actual unit demand - Forecast) + ABS (Year 3 actual unit demand - Forecast) + ABS (Year 4 actual unit demand - Forecast)]/ Number of years

Let plug in the formula

MAD = [ABS(100 - 120) + ABS (105 - 120) + ABS (135 - 120) + ABS (150 - 120)]/4

MAD =(ABS 20) + (ABS 15) + (ABS 15) + (ABS 30)/4

MAD= 80/4

MAD=20

Therefore the resulting MAD value that can be computed from this data is 20

8 0

3 years ago

2x²-5x-12=0 (simplify solution set)

Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

$ax^2+bx+c=0$

Let's find a, b, c:

a is the coefficient of x^2
b is the coefficient of x
c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}$

$x=\frac{5\pm\sqrt{121} }{4}$

$x=4$ or $x=\frac{-3}{2}$

<u />

<u>Answer:</u>

x = 4 or x = -3/2

7 0

1 year ago

Qual a resposta dessa expressão numérica? 3-10³-3.10².2².1²

Len [333]

I don't understand your language and I don't know which language is this but I try to answer your question. 3-1000-3*100*4*1 3-1000-1200 3-2200 =-2197

6 0

3 years ago

Solve 3(4x-1)=12x +7

telo118 [61]

Answer:

there are no solutions

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers