All categories

3 years ago

Trey has plastic cubes stored in a box that measures

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

It's 160 (D) hope this helps

Sladkaya [172]3 years ago

5 0

Your answer is D.160

You might be interested in

The volume of a barrel of oil is 0.22 m^3. If the height of the barrel is 0.84 m, what is the radius to the tenths place? Please

Lena [83]

V = pi * r^2 * h
.22 = 3.14 * r^2 * .84
.22 = 2.6 r^2
divide both sides by 2.6
.08 = r^2
r = .3 the radius is approximately .3 m

CHECK
V = 3.14 * .3^2 * .84
V = .24 m^3

7 0

4 years ago

PLEASE HELP ASAP!!!! WILL GIVE BRAINLIEST

marusya05 [52]

Answer:

6 days

210 pages

Step-by-step explanation:

As stipulated by the question, let the number of days Amir has been reading be x and the number of pages he had read to be y.

Now since he reads 35 pages per day.

7 0

3 years ago

Read 2 more answers

TRANSFORM THE GIVEN QUADRATIC FUNCTION INTO THE FORM y=a(x-h)²+k <br>1. y=x²+4x+5

Kazeer [188]

Answer:

(x²-2)+1

Step-by-step explanation:

(x²-2)-2²+5

(x²-2)+1

7 0

3 years ago

Heelllllllllpppppppp meeeeeeee

Nadya [2.5K]

Answer:

options b ... on the y axis only the x coordinate is always 0

4 0

3 years ago

Read 2 more answers

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

4 years ago