<span>1. (f+g)(x) = f(x) +g(x)
.. = (</span>x^2-36) +(<span>x^3+2x^2-10)
.. = x^3 +3x^2 -46
2. </span>(f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81
<span>3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10</span>
Step-by-step explanation:
hope this help have a great day
First isolate y by adding x to both sides in y-x=3 and getting y=x+3
Step 1: substitute x+3 for y in 3y=x+6 to get 3(x+3)=x+6
Step 2: distribute 3x+9=x+6
Step 3: subtract like terms 2x=-3
Step 4: divide x=-3/2
substitute -3/2 for x in y=x+3 to get
y=-3/2+3
y=3/2
answer: y=3/2 x=-3/2
Answer:
The answer to the question provided is 5 units.
Answer:
2/3
Step-by-step explanation:
Let n = the repeating, non-terminating number 0.666...
We now have n = 0.666666...
We want the number n in the form of a fraction.
Since only 1 digit repeats, the 6, use a 1 followed by 1 zero, which means the number 10. Now multiply both sides by 10 and write the original equation below it.
10n = 6.666666...
n = 0.666666...
Subtract the bottom equation from the top equation.
9n = 6
n = 6/9
n = 2/3
