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3 years ago

TRANSFORM THE GIVEN QUADRATIC FUNCTION INTO THE FORM y=a(x-h)²+k 1. y=x²+4x+5

Mathematics

1 answer:

Kazeer [188]3 years ago

7 0

Answer:

(x²-2)+1

Step-by-step explanation:

(x²-2)-2²+5

(x²-2)+1

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I kinda forgot my trig (kinda)

Ipatiy [6.2K]

$\sec^2\theta=1+\tan^2\theta\implies \sec\theta=\pm\sqrt{1+\tan^2\theta}$

Since $\cos\theta>0$ for $0$ , we have $\sec\theta>0$ , so we take the positive root. Now,

$\sec\theta=\sqrt{1+\left(\dfrac{12}5\right)^2}=\dfrac{13}5$

- - -

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$
$\cos^2\theta=1-\sin^2\theta$

In the first quadrant, cosine is positive, so

$\cos\theta=\sqrt{1-\sin^2\theta}$

and in turn,

$\sin\theta=\dfrac35\implies\cos\theta=\sqrt{1-\left(\dfrac35\right)^2}=\dfrac45$
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In the previous problem, we had $\cos\theta=\dfrac45$ , so we must have $\tan\theta=\dfrac34$ , which means

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3 years ago

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Shtirlitz [24]

Answer:

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Step-by-step explanation:

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3 years ago

Eight more then the quotient of a number and 6 is 1

miv72 [106K]

Answer:

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Step-by-step explanation:

quotient of a number and 6: x/6

8 more then the quotient of a number and 6 is 1: x/6 + 8= 1

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multiply both sides by 6 to isolate x

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4 years ago

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TRANSFORM THE GIVEN QUADRATIC FUNCTION INTO THE FORM y=a(x-h)²+k 1. y=x²+4x+5 ​

TRANSFORM THE GIVEN QUADRATIC FUNCTION INTO THE FORM y=a(x-h)²+k 1. y=x²+4x+5