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ziro4ka [17]
3 years ago
15

Which expression is equivalent to the following complex fraction?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

what a mess?!

please write your question better...

if you don't want the wrong answer

Step-by-step explanation:

what should we do?

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30 ⅓ % of 3 plz help me
Vikki [24]

Answer:

3 / 10 is the answer in fraction and 0.3 is the answer in decimal.

Step-by-step explanation:

hope this answer will help you

have a great time

5 0
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How do you 92 = 8(f + 2) – 4 ?????
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A sequence is defined by f(0) = -20, f(n) = f(n-1) - 5 forn > 1.
bulgar [2K]

Answer:

1. Proved down

2. proved down

3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5

Step-by-step explanation:

Let us explain how to solve the question

∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1

→ That means we have an arithmetic sequence with constant

   difference -5 and first term -20

1. → f(1) means we need to find the second term, which equal the

      term - 5

∵ f(1) means n = 1

∴ f(1) = f(1 - 1) - 5

∴ f(1) = f(0) - 5

∵ f(0) = -20

∴ f(1) = -20 - 5 → Proved

2. → f(3) means we need to find the third term, which equal the

   second term - 5

∵ f(3) means n = 3

∴ f(3) = f(3 - 1) - 5

∴ f(3) = f(2) - 5

→ f(2) = f(1) - 5

∵ f(1) = -20 - 5

∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5

∴ f(3) = [-20 - 5 - 5] - 5

∴ f(3) = -20 - 5 - 5 - 5 → Proved

3. → From 1 and 2 we notice that the number of -5 is equal to n,

      at n = 1 there is one (-5), when n= 3 there are three (-5)

∵ n = 10

∴ There are ten (-5)

∴ f(10) = -20 - 5(10)

∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved

6 0
3 years ago
Will mark brainliest help!
kakasveta [241]

Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

3 0
3 years ago
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