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3 years ago

Pls ill give brainelist

Mathematics

2 answers:

goblinko [34]3 years ago

7 0

Answer:

Vertical angle

Step-by-step explanation:

nasty-shy [4]3 years ago

7 0

Answer:

C. Alternate exterior.

Step-by-step explanation:

we know it can't be A. supplementary because that would be angle 2 and 4 or 1 and 3 (etc). It cant be B. verticle because that would be like 6 and 7 or 2 and 3 (etc). and it cant be D. Alternate interior angles because that would be 3 and 6 or 5 and 4 (etc). so the answer is C. alternate exterior.

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If a =2, find 4a + 18

FinnZ [79.3K]

4×2+18

= 8+18

=26....

answer is 26..

6 0

2 years ago

Read 2 more answers

Should be easy points!

Andru [333]

Answer:

Let x represent the number from the sentence.

Step-by-step explanation:

2(x) + 2(1/x) = 20/3

2x + 2/x = 20/3

multiply both sides of the equation by 3x

6x + 6 = 20x

6x - 20x + 6 = 0

6x - 18x - 2x + 6 = 0

6x(x-3 -2(x-3) = 0

(6x-2 = 0 or x-3 = 0

6x = 2 or x = 3

x = 2/6

x = 1/3

Since x represented the number

Therefore x = 1/3 or 3

4 0

3 years ago

A company donates 2,292 gifts to a school. the gifts are diveded evenly among 19 classrooms. The rest of the gifts are given to

BARSIC [14]

Answer:

Each classroom received 120 gifts and the hospital received 12 gifts

Step-by-step explanation:

Division As Evenly Distribution

The first concept we manage when learning about divisions is how to distribute an amount N among m elements such as everyone receives the same amount.

If the nature of the problem allows distributing decimal portions of N, then every receiver gets exactly the same amount N/m.

But things are different when the division must be an integer number. For example, if we wanted to divide gifts, we cannot give partial gifts. So the correct division is a matter of the study of integer numbers.

If N is divisible by m, i.e. there is no remainder in the division, then each element will receive N/m gifts. But what if they are not divisible? We must divide and take the integer part of the division and discard the remainder

We want to divide 2,292 gifts to the school, where there are 19 classrooms. If we divide 2,292/19 we get 120 and a remainder of 12.

Answer. Each classroom received 120 gifts and the hospital received 12 gifts

6 0

3 years ago

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi

My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

$S_n = \frac{n}{2}(2a_1 +(n-1)d)$

Sn = 5510, n=10 n d= 100 we need to find out first term a1

$5510 = \frac{10}{2}(2a_1 +(10-1)100)$

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

$a_n = a_1 + (n-1) d$

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0

4 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago