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FinnZ [79.3K]
3 years ago
9

tiffany answered 90 percent of the questions on the math test correctly. there were 50 questions in total. how many questions di

d tiffany answer correctly. show work.
Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0
Hi!

Use the percentage formula to solve:

90 * 50 / 100 = 45

Tiffany answered 45 questions correctly.
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How to find a discount percent
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If they give you the total price and the price after the discount you can use this "formula" to solve it p/100=b/a where p is the percentage, a is the total price and b is the price after the discount.
3 0
2 years ago
Which of the statements best compares the pairs of perpendicular and parallel lines?
Sergeu [11.5K]
Wich statements. Let me know

8 0
3 years ago
Read 2 more answers
Which of the following is equivalent
Aloiza [94]

Answer:

5 1/4 times 1/2 = 2.625. as a fraction 2.625 is 2 5/8 because  .625 could be drawn out to 625/1000 125 goes into 625 and 1,000    625 divided by 125 = 5 and 1,000 divided by 125 is 8 we already had 2 so 2 5/8

Step-by-step explanation:

8 0
3 years ago
If G is the midpoint of FH find FG<br>fg=11x-7 gh= 3x+9
gavmur [86]

Solution:

we are given that

If G is the midpoint of FH,  it mean that

FG=GH

we are also given that

FG=11x-7 ,GH= 3x+9

So we can write

11x-7=3x+9\\&#10;\\&#10;11x-3x=7+9\\&#10;\\&#10;8x=16\\&#10;\\&#10;x=2

So FG=11x-7=11*\frac{1}{2}-7=11*2-7=15


3 0
3 years ago
The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim
Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

34.5 + 20.75 + 24.75 = 80cm.

Hope this helped.

3 0
2 years ago
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