Answer:
The distance between of the park to the school is approximately 8.6 miles
Step-by-step explanation:
The given information are;
The location of the school from the house = 4 miles East and 1 mile South
The location of the park from the house = 3 miles East and 4 mile South
By representing the direction East (x-direction) as being in the direction of vector and the direction South (negative y-direction) as being in the direction of vector , we have;
The location of the school from the house = 4· +
The location of the park from the house = 3· + 4·
The distance, l, between the park and the school is given by the resultant of the two vectors as follows
= 4· + 3·
= + 4·
Therefore,
The distance between of the park to the school ≈ 8.6 miles.
Answer:
E 14/15
Step-by-step explanation:
3/5 = 9/15
1/3 = 5/15
The unit circle is defined by the equation
... x² + y² = 1
Then
... y = √(1 -x²) = √(1 -0.12²) = √0.9856
... y ≈ 0.99
Answer:
61 c
Step-by-step explanation:
Circumference= 2πr = πd=3.14d
- 25 c, d = 24.3 mm ⇒ C=24.3*3.14 = 76.302
- 10 c, d = 17.9 mm ⇒ C=17.9*3.14 = 56.206
- 5 c, d = 21.2 mm ⇒ C=21.2*3.14 = 66.568
- 1 c, d = 19.1 mm ⇒ C=19.1*3.14 = 59.974
1*10 c+ 2*25 c+ 1*1 c = 61 c