Complete question:
1). Determine the character states for the following six characters that are present in species OG, 5, 7, 15, 17, 18. Assign the character state found in the outgroup (OG) as a 0 and the alternative derived state a 1; use only two states per character. Example, stem width: 0 = thin, / = thick 1 <em>(Characters and plant species image in the attached files)</em>
2). Score each taxon using the 0 and 1 notation about and add to this matrix <em>(Matrix in the attached files)</em>
4). Reconstruct the phylogeny that most simply and accurately accounts for the distribution of synapomorphies among ingroup species. Given matrices as small and simple as the above example, one can build the tree from the bottom up in a series of sketches, adding clades or branches representing groups with the fewest synapomorphies near the base of the tree and those with the most at the tips. Using the unlabeled phylogeny as a starting point, draw the stepwise construction of a fully resolved phylogeny to account for all of the synapomorphies and include the synapomorphies that identify each clade (the first one, character 2, is included to get you started; this is shared by all members of the ingroup) (<em>Tree in the attached files)</em>
Answer:
- Stem width: Thick-1 // Thin-0
- Leaf edge (shape): Pointed-1 // Blunt-0
- Flower base (shape): Narrow-0 // Wide-1
- Flower orientation: Downward (Pendant)-1 // Upward (Vertical)-0
- Petal color: Purple-1 // Yellow-0
- Fruit shape (inset on card, on left): Round-0 // Elongated-1
- Complete Matrix in the attached files
- Order in the phylogeny reconstruction: OG --> 7 --> 5 --> 15 --> 17 and 18 (tree + evolutive changes in the attached files)
Explanation:
<em>NOTE: You will find the complete activity in the attached files. </em>
- The principle of maximum parsimony or maximum simplicity states that among all possible trees within a group of species, the most probable is the one that requires us to postulate the least number of evolutionary changes. So, to reconstruct a phylogeny we need to choose the tree that requires the less number of changes.
- To determine the character states for all the six characters, we assigned the number cero to all the characters expressed in the out-group. Thin steam, blunt leaf, narrow flower base, upward flower orientation, yellow petals, and rounded-seeds are all cero states. The other characters are 1.
- The above information of character state was used to fill in the matrix, specifying which character state belongs to each species according to their traits.
- The matrix was useful to reconstruct the phylogeny, to identify the autapomorphic trait, and to visualize all the clades.
Answer:
Explanation:
Not only is the biota important, but the abiotic factors in the ocean are also important because both groups work together. The abiotic factors in the ocean help the ocean to 'work'. For example, phytoplankton (autotrophs) need light, nutrients, CO2 (dissolved gases) to photosynthesize.
Telophase II begins after the separation of sister chromatids. In this phase individual chromosomes reach at pole. Nuclear membrane starts getting formed around them and cytokinesis takes place. Cytokinesis is the division of cytoplasm.
This results in the formation of four daughter cells which are haploid.
Answer:
"Long, bitterly cold, dry winters and short, cool, damp summers define the boreal forest climate. The boreal forest is alive with activity. In the winter, their conical forms decrease snow buildup on branches, preventing them from breaking under the weight of the snow."
Explanation:
Hope this helps! :)
Explanation:
Proteins and nucleic acids play important biological functions : they catalyze and regulate reactions, transport substrates, code and transcribe genetic information. It is widely appreciated that water molecules play an invaluable role in governing the structure, stability, dynamic, and function of these biomolecules
Water, without any doubt, must be considered an integral part of biological macromolecules. The living world should be thought of as an equal partnership between proteins, nucleic acids and water