Answer:
The answer is "The LMI model should be compatible with the supplier dynamically for the network manager".
Explanation:
The term LMI stands for the "Local Management Interface", it is a Cisco technology, in which the signaling protocol was used in between routers and transmission frame switches to share data in timekeepers, global addressing, multipathing as well as the present state of virtual socks for various purposes, in which it is mainly used for "dynamically setting, in which the network administrator provides compatibility with the service provider".
Adding a table to a document can be done in Microsoft Word using the insert ribbon, the insert ribbon are mostly used for adding options to a document.
- The insert ribbon is a multi functional ribbon which has up to about 10 different useful groups for adding elements to a document.
- Some of the groups on the insert ribbon include ; Pages, Text, Header & Footer, Tables, illustrations, Links, Media and so on.
- The Table group in the insert ribbon allows different table adding options such as inserting an already existing table, drawing a new table or importing an excel table.
Therefore, adding a table to a document is performed from the insert ribbon in Microsoft Word.
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So assuming you were buying this piece of trash with the mouse and keyboard it would be around $450. Average pay per hour is $9.10-$10.20 depending on were you live so we will just say $9.50. You'd need to work rougly 47 hours (without taxes) So i'd say 65-75 Hours.
Answer:
The complete method is as follows:
public static int divBySum(int[] arr, int num){
int sum = 0;
for(int i:arr){
if(i%num == 0)
sum+=i;
}
return sum;
}
Explanation:
As instructed, the program assumes that arr has been declared and initialized. So, this solution only completes the divBySum method (the main method is not included)
This line defines the method
public static int divBySum(int[] arr, int num){
This line declares and initializes sum to 0
int sum = 0;
This uses for each to iterate through the array elements
for(int i:arr){
This checks if an array element is divisible by num (the second parameter)
if(i%num == 0)
If yes, sum is updated
sum+=i;
}
This returns the calculated sum
return sum;
}
