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C. a payday lender is a type of loan
Time, due to the amount of time between the initial action and the filing of the report, federico could claim the it didn't happen or something
Answer:
alphabets = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
newList = []
N = 3
for i in range(N):
newList.append(alphabets[i] * 3)
print(newList)
Explanation:
- Initialize the alphabets.
- Use a for loop to append three alphabets to new list.
- Finally print the new list.
Answer:
#include <iostream>
#include <vector>
using namespace std;
/* Define your function here */
vector<int> GetUserValues(vector<int>& userValues, int numValues) {
int tmp = 0;
vector<int> newVec;
for(int i = 0; i < numValues; i++) {
cin >> tmp;
newVec.push_back(tmp);
}
return newVec;
}
void OutputIntsLessThanOrEqualToThreshold(vector<int> userValues, int upperThreshold) {
for (int i = 0; i < userValues.size(); ++i) {
if(userValues.at(i) < upperThreshold) {
cout << userValues.at(i) << " ";
}
}
cout << endl;
}
int main() {
vector<int> userValues;
int upperThreshold;
int numValues;
cin >> numValues;
userValues = GetUserValues(userValues, numValues);
cin >> upperThreshold;
OutputIntsLessThanOrEqualToThreshold(userValues, upperThreshold);
return 0;
}
Explanation:
Perhaps their is a better way to code this, but I couldn't figure out what to do with the pointer in the first function.