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ankoles [38]
3 years ago
7

What is created for each user the first time the user logs onto windows?

Computers and Technology
1 answer:
Naddik [55]3 years ago
4 0
<span>A profile is made the first occasion when that a client sign on to a Windows XP, Windows 2000, or Windows NT® Workstation–based PC. A client profile is a gathering of settings and documents that characterizes the condition that the framework loads when a client sign on. It incorporates all the client arrangement settings, for example, program things, screen hues, organize associations, printer associations, mouse settings, and window size and position. Profiles are not client arrangements and the client has a profile regardless of the possibility that you don't utilize Group Policy.</span>
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Write an application that determines which, if any, of the following files are stored in the folder where you have saved the exe
Elza [17]

Answer:

Here is the JAVA application that determines which if any of the following files are stored in folder where you have saved the exercises created.

import java.nio.file.*;   // used to manipulate files and directories

import java.nio.file.attribute.*;  //used to provide access to file and file attributes

import static java.nio.file.AccessMode.*;  // provides access modes to test the accessibility of a file

import java.io.IOException;  //for exception handling

class FindSelectedFiles {

public static void main(String[] args) { //start of main function

   Path f1 = Paths.get("/root/sandbox/autoexec.bat"); //creates Path object f1 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f2 = Paths.get("/root/sandbox/CompareFolders.java");  //creates Path object f2 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f3 = Paths.get("/root/sandbox/FileStatistics.class");   //creates Path object f3 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f4 = Paths.get("/root/sandbox/Hello.doc"); //creates Path object f4 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   int count=0; //used to count the number of files found  

try{  // used to define a code chunk to be tested for errors

 f1 = Paths.get("/root/sandbox/autoexec.bat");  // Converts a path string when joined form a path string to a Path

 System.out.println(f1);  //prints the file

     /* getFileSystem method is used to return the file system that created this Path object f1 and checkAccess Verifies access and throws exception if something is wrong

 f1.getFileSystem().provider().checkAccess(f1);  

 System.out.println(f1 +" File Exists\n");  //if file exists then displays this message

 count++;  }  //adds 1 to the count of number of files found

 catch (IOException e) {  //a code chunk to be executed if error occurs in the try part

  System.out.println("File Doesn't Exist\n"); }  //if file not found displays this message

   

try{  //works same as above try block but for 2nd folder and object f2

 f2 = Paths.get("/root/sandbox/CompareFolders.java");

 System.out.println(f2);

 f2.getFileSystem().provider().checkAccess(f2);

 System.out.println(f2 +" File Exists\n");

 count++;  }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 3rd folder and object f3

 f3 = Paths.get("/root/sandbox/FileStatistics.class");

 System.out.println(f3);

 f3.getFileSystem().provider().checkAccess(f3);

 System.out.println("File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 4th folder and object f4

    f4 = Paths.get("/root/sandbox/Hello.doc");

    System.out.println(f4);

 f4.getFileSystem().provider().checkAccess(f4);

 System.out.println(f4 +" File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

   System.out.println(count+" of the files exist");  }  } //displays the number of files found

Explanation:

If you want to directly pass the file name as argument to Paths.get() method then you can use the following code:

   Path f1 = Paths.get("autoexec.bat");

   Path f2 = Paths.get("CompareFolders.java");

   Path f3 = Paths.get("FileStatistics.class");

   Path f4 = Paths.get("Hello.doc");

The program determines if any, of the files from autoexec.bat, CompareFolders.java, FileStatistics.class, and Hello.doc. are stored in the folder. If a file is found then the program displays the message File exists and add 1 to the count variable each time a file is found. If all the files are found then the program returns the count as 4 otherwise the program display the number of files found by displaying the computed final value of count in the output. Lets say all the files are found then the output of the above program is:

autoexec.bat                                                                                                                                                   autoexec.bat File Exists  

                                                                                                                                                      CompareFolders.java                                                                                                                                            CompareFolders.java File Exists                                                      

                                                                                                                                                         FileStatistics.class                                                                                                                                           File Exists                                                                                        

                                                                                                                                                     Hello.doc                                                                                                                                                      Hello.doc File Exists  

   

4 of the files exist    

8 0
3 years ago
Write a recursive function that calculates if two binary trees are similar?
ahrayia [7]

Answer:

bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.

{

   if(root1==NULL&&root2==NULL)//both trees are null means identical.

   return true;

   if(roo1 && root2)

   {

       if(root1->data==root2->data)//condition for recursive call..

       {

           return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);

       }

   }

   else

   return false;

}

Explanation:

In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.

If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.

else returning false.

5 0
3 years ago
The term packet is used fairly generically to refer to protocol data unit (PDU). There are PDU equivalent names in the different
Westkost [7]

Answer:

Bits

Explanation:

The protocol data unit is the representative unit of data in the OSI layer of a network. The OSI system has seven layers.

The physical layer is the first layer of the system and the protocol data unit is represented as bits of data.

Note that the term packet is the PDU for data in the network layer of the OSI network system.

4 0
2 years ago
4. You are planning to buy a new couch for your family room. Before you leave for the furniture store, you measure the available
zysi [14]
First, convert feet to inches. The ' denotes foot measurement while the " denotes inches. Since there are 12 inches in a foot,

5'10" = (5*12) + 10 = 70 inches
6'8" = (6*12) + 8 = 80 inches

a.) The lower limit is 70 inches while the upper limit is 80 inches.
b.) First, divide 78 inches by 12. That would 6.5 or 6 and a half feet. Since half foot is 6 inches, the length of the couch is 6'-6"
c.) Since the couch is between the limits, yes it would fit the space.

7 0
3 years ago
98 points possible
joja [24]

A programming language is not used to talk from human to human. It is used to talk from a human to a computer. Computers are very dumb compared to us, so they need to be taught or spoken to in simple terms. Asking them something complex is far beyond their understanding, as they cannot learn anything beyond what has already been taught to them. Using print: “Hello, World” is the way to tell them to do stuff way less complex than when we say ‘write the words Hello, World on the screen’. A programming language is also not very easy to create. Talking to a computer in a dumb way reduces the process to make a new language for the computer to understand.

6 0
3 years ago
Read 2 more answers
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